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Question

The number of Cl and Ca+2 ions in 222g. of CaCl2 are


A

4N, 2N

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B

2N, 4N

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C

1N, 2N

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D

2N, 1N

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Solution

The correct option is A

4N, 2N


No. of molecules = 222111 × N = 2N

CaCl2 Ca+2 + 2Cl

No. of Cl ions = 2 × 2N = 4N

No. of Ca+2 ions = 2N


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