The number of Cl− and Ca+2 ions in 222g. of CaCl2 are
4N, 2N
2N, 4N
1N, 2N
2N, 1N
No. of molecules = 222111 × N = 2N
CaCl2 → Ca+2 + 2Cl−
No. of Cl− ions = 2 × 2N = 4N
No. of Ca+2 ions = 2N