Question

The number of $C{l}^{-}$ and $C{a}^{+2}$ ions in 222g. of $CaC{l}_2$ are

• A. 4N, 2N
• B. 2N, 4N
• C. 1N, 2N
• D. 2N, 1N

Answer 1

The correct option is A

4N, 2N

No. of molecules = $\frac{222}{111}\times N$ = $2N$

$CaC{l}_2\to C{a}^{+2}+2C{l}^{-}$

No. of $C{l}^{-}$ ions = $2\times 2N$ = $4N$

No. of $C{a}^{+2}$ ions = $2N$