The number of common solutions for the system of linear equations $5 x + 4 y + 6 = 0$ and
$10 x + 8 y = 12$ is ___

0

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

1

No worries! We‘ve got your back. Try BYJU‘S free classes today!

infinite

No worries! We‘ve got your back. Try BYJU‘S free classes today!

None of these

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $0$
Clearly both the equations are parallel to each other as
$10 x + 8 y = 12 => 2 (5 x + 4 y = 6)$
which has the same coefficients of x and y as $5 x + 4 y + 6 = 0$
Two parallel lines never intersect and do not have any solutions.
So, the number of common solutions for the given system of linear equations is $0$ .

Suggest Corrections

Similar questions

5 x + 4 y = 20

10 x + 8 y = 16

Solution for the following pair of linear equations is:
2x + 4y = 8
4x + 8y = 0

5 x + 2 y = k; 10 x + 4 y = 3

Total number of solutions to the system of linear equations x + y + 0.z = 0, X – y + 0.z = 0, X + 4y + 0.z = 0 is 1.

5 x + 7 y = 12

10 x + 14 y = 20

Join BYJU'S Learning Program