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Question

The number of common tangents to the circles x2+y26x14y+48=0 and x2+y26x=0 is

A
1
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B
2
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C
0
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D
4
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Solution

The correct option is D 4
C1=(3,7),r1=9+4948=10,C2=(3,0),r2=32=3
C1C2=7,r1+r2=3+10<3+4=7
Clearly C1C2>r1+r2.
Hence there will be four common tangents.

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