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Question

The number of common terms to the series 3+7+11++2019 and 1+6+11++2021 is

A
101
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B
90
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C
120
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D
98
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Solution

The correct option is A 101
For first series,
a1=3,d1=4
For second series,
a2=1,d2=5
For both series, first common term =11
Second common term =11+LCM(4,5)=31
So, the common term sequence is 11,31,51,
Last term 2019,
11+(n1)202019
n101.4
Hence, the number of common terms is 101

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