The number of complexes that can be can be made with varying $N H_{3}$ ligands to satisfy primary and secondary valencies of platinum are:
Complex; [ $P t C l_{4} \cdot x N H_{3}$ ]

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Solution

The correct option is A 5
The correct answer is 5.
The number of complexes that can be can be made with $P t C l_{4} \cdot x N H_{3}$ are :
I. $[P t (N H_{3})_{6}] C l_{4}$

II. $[P t (N H_{3})_{5} C l] C l_{3}$

III. $[P t (N H_{3})_{4} C l_{2}] C l_{2}$

IV: $[P t (N H_{3})_{3} C l_{3}] C l$

V: $[P t (N H_{3})_{2} C l_{4}]$

Option A is correct.

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Similar questions

[P t (e n)_{2} C l_{2}]

C o C l_{3} \cdot 5 N H_{3}

C l^{-}

C o C l_{3} \cdot 5 N H_{3}

C l^{-}

[C o (N H_{3})_{4} C l_{2}] C l

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