The number of compounds given below that belong to same homologous series are
$C H_{2} O_{2}, C_{3} H_{8} O, C_{2} H_{4} O_{2}, C_{2} H_{6}, C_{3} H_{6} O_{2}, C_{5} H_{10} O_{2}, C_{3} H_{8}$

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Solution

The correct option is A
4

Homologogous series is a series of compounds having the same functional group and the successive members of which differ by - $C H_{2}$ group.
$H C O O H (C H_{2} O_{2}), C H_{3} C O O H (C_{2} H_{4} O_{2}), C H_{3} C H_{2} C O O H (C_{3} H_{6} O_{2}), C H_{3} C H_{2} C H_{2} C H_{2} C O O H (C_{5} H_{10} O_{2})$

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Similar questions

{CH}_{2} O_{2}, C_{3} H_{8} O, C_{2} H_{4} O_{2}, C_{2} H_{6}, C_{3} H_{6} O_{2}, C_{4} H_{8} O_{2}

{CH}_{2} O_{2}, C_{3} H_{8} O, C_{2} H_{4} O_{2}, C_{2} H_{6}, C_{3} H_{6} O_{2}, C_{4} H_{8} O_{2}

{CH}_{2} O_{2}, C_{3} H_{8} O, C_{2} H_{4} O_{2}, C_{2} H_{6}, C_{3} H_{6} O_{2}, C_{4} H_{8} O_{2}

C_{3} H_{6} O_{2}

C_{3} H_{8} O

C_{2} H_{6}, C_{2} H_{6} O, C_{2} H_{6} O_{2}, C H_{4} O

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