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Question

The number of consecutive zeros in 23 ×34 ×54 ×7, is

(a) 3

(b) 2

(c) 4

(d) 5

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Solution

We are given the following expression and asked to find out the number of consecutive zeros

We basically, will focus on the powers of 2 and 5 because the multiplication of these two number gives one zero. So

23×34×54×7=23×54×34×7=23×53×5×34×7=2×53×5×34×7=103×5×34×7=5×81×7×1000=2835000

Therefore the consecutive zeros at the last is 3

So the option (a) is correct


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