Question

The number of coulombs necessary to deposit 1 g of potassium metal (molar mass $39gmo{l}^{-1}$) from $K^{+}ions$ is:

• A. ${96500}^{o}C$
• B. $1.93\times {10}^5$${}^{o}C$
• C. $1237$${}^{o}C$
• D. $2474$${}^{o}C$

Answer 1

The correct option is D $2474$${}^{o}C$

$MassDeposited=1g$

$n=1$ $\left(K^{+}ions\right)$; $K^{+}+e^{-}\to K$

$Molarmass=39gmo{l}^{-1}$

$m=\frac{AtomicMass}{n\times F}\times i\times t$

$1=\frac{39}{1\times 96500}\times i\times t$

$\frac{96500}{39}=i\times t$

$i\times t=2474.35C$

The number of coulombs necessary to deposit $1g$ of potassium metal from $K^{+}$ ions is $2474{}^{o}C$