The number of coulombs required to reduce $12.3 g$ of nitrobenxene to aniline is :

115000 C

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5700 C

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57900 C

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Solution

The correct option is C $57900 C$
Reaction for reduction :

$C_{6} H_{5} {N O}_{2} + {6 H}^{+} + 6 e^{-} ⟶ C_{6} H_{5} {N H}_{2} + 2 H_{2} O$

Given, molar mass of $C_{6} H_{5} {N O}_{2} = 123$

Here, $12.3 g$ nitrobenzene mole $= \frac{6 \times 12.3}{123} = 0.6$

$∴$ Charge $= 0.6 \times 96500$ coloumbs
$= 57900$

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