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Standard XII
Chemistry
Ostwald Dilution Law
The number of...
Question
The number of degrees of freedom of the linkage shown in the figure is
A
-3
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B
0
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C
1
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D
2
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Solution
The correct option is
C
1
Degree of freedom:
F
=
3
(
6
−
1
)
−
2
×
7
−
0
=
15
−
14
=
1
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2
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