The number of diagonals in a polygon of m sides is

\frac{1}{2!} m (m - 5)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{1}{2!} m (m - 1)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{1}{2!} m (m - 3)

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

\frac{1}{2!} m (m - 2)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $\frac{1}{2!} m (m - 3)$
Required number of diagonals $=^{m} C_{2} - m$
$= \frac{m (m - 1)}{2!} - m = \frac{m}{2!} (m - 3)$

Suggest Corrections

Similar questions

20 m^{2}

m m^{2}

{m m}^{2}

18 m m, 24 m m

30 m m

m m^{2}

2 \sqrt{2}

Join BYJU'S Learning Program