Question 2
The number of diagonals in a septagon is
a) 21
b) 42
c) 7
d) 14

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Solution

A diagonal is a line segment joining two opposite corners of a polygon.

Number of diagonals in a polygon = $\frac{n (n - 3)}{2}$
A septagon is a polygon having seven sides.
i.e. n=7
$∴$ Number of diagonals in a septagon = $\frac{7 (7 - 3)}{2}$ = $\frac{7 \times 4}{2}$ = 14

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Q. Compute the median from the following data:

Marks	0-7	7-14	14-21	21-28	28-35	35-42	42-49
Number of students	3	4	7	11	0	16	9

Compute the median from the following data:
$\begin{matrix} Marks & 0 - 7 & 7 - 14 & 14 - 21 & 21 - 28 & 28 - 35 & 35 - 42 & 42 - 49 Numbers of students & 3 & 4 & 7 & 11 & 0 & 16 & 9 \end{matrix}$

Question 2
The number of diagonals in a septagon is
a) 21
b) 42
c) 7
d) 14

Question 2
The number of diagonals in a septagon is
a) 21
b) 42
c) 7
d) 14

Q. The number of diagonals in a septagon is

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Question 2 The number of diagonals in a septagon is a) 21 b) 42 c) 7 d) 14

A diagonal is a line segment joining two opposite corners of a polygon. Number of diagonals in a polygon =n(n−3)2 A septagon is a polygon having seven sides. i.e. n=7 ∴ Number of diagonals in a septagon = 7(7−3)2 =7×42 = 14

Question 2
The number of diagonals in a septagon is
a) 21
b) 42
c) 7
d) 14

A diagonal is a line segment joining two opposite corners of a polygon.

Number of diagonals in a polygon = $\frac{n (n - 3)}{2}$
A septagon is a polygon having seven sides.
i.e. n=7
$∴$ Number of diagonals in a septagon = $\frac{7 (7 - 3)}{2}$ = $\frac{7 \times 4}{2}$ = 14