Question

The number of different numbers each of six digits that can be formed by using all the digits 1, 2, 1, 0, 2, 2 is:

• A. $600$
• B. $120$
• C. $100$
• D. $50$

Answer 1

Answer: (D)

$50$

First place of a number should not be one, 2 is repeating thrice and 1 is repeating twice

$\therefore$Total number of ways of permuting $=\frac{5\times 5\times 4\times 3\times 2\times 1}{3!\times 2!}=50$