Question

The number of different possible orders of matrices having $18$ elements and all are identical is:

• A. $3$
• B. $1$
• C. $6$
• D. $4$

Answer 1

The correct option is C $6$

Total elements in the matrix $=18$
Let order of the matrix $=(m\times n),(m,n\in N)$
$\therefore 18=m\times n$ (where $m=$ number of rows and $n=$ number of columns)
Hence, possible values of $m$ and $n$ are:
$m=18,n=1m=1,n=18m=6,n=3m=3,n=6m=2,n=9m=9,n=2$
$\Rightarrow$Total number of possible orders $=6$