Question

The number of different possible orders of matrices having 18 identical elements is

• A. 3
• B. 1
• C. 6
• D. 4

Answer 1

The correct option is C 6

Let the order of the matrix is $(a\times b)$

There are $18$ elements in the matrix.

So, $a\times b=18$

Possible orders can be $(1\times 18),(18\times 1),(2\times 9),(9\times 2),(3\times 6),(6\times 3)$

There are $6$ possible orders.