Question

The number of different six digit numbers that can be formed with 4, 5, 6, 7, 8, 9 such that it is not divisible by '5' is (repetition is not allowed)

• A. $120$
• B. $720$
• C. $600$
• D. $100$

Answer 1

Answer: (C)

$600$

Number ending with $0$ or $5$ is divisible by $5$.
Unit place of $6$ digit number not divisible by $5$ must have any number apart from $0$ or $5$.
$\therefore$ Number of ways $=1\times 2\times 3\times 4\times 5\times 5=600$