Question

The number of different six digit numbers, the sum of whose digits is odd is

• A.
• B.
• C.
• D.

Answer 1

The correct option is D

The number of different six digit numbers are $9\times {10}^5$ in which half of them will have sum of digits even and half of them odd and hence required number is $\frac{9\times {10}^5}{2}=45\times {10}^4$