Question

The number of digit '1' present in the binary representation of the number $(199{)}_{16}$ is

• A. 3
• B. 4
• C. 5
• D. 6

Answer 1

The correct option is C 5

$(199{)}_{16}=(409{)}_{10}$

$(409{)}_{10}=256+128+0+0+16+8+0+0+1$

$=1\times 2^8+1\times 2^7+2^4+1\times 2^3+1\times 2^0$

$(409{)}_{10}=(110011001{)}_2$

Total number of 1's = 5