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Question

The number of digits in 20301 (given log102=3.010) is

A
602
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B
301
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C
392
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D
391
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Solution

The correct option is C 392
Let x=20301
Taking log both sides, we get
logx=301log20
logx=301(log2+log10)
logx=301(.3010+1)
logx=391.601
Number of digits in 20301=391+1=392

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