The number of digits in 484- 512 is

The correct option is B 16 4log ( 48 )=6.724 5log ( 12 )=8.387 Now nbsp; take the digit and add 1 6+1 =7 nbsp; and nbsp; 8+1=9 Total ...

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The number of digits in $(48^{4} \times 5^{12})$ is

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(459 \times 46 \times 25 \times 28 @ \times 484)

2

459 \times 46 \times 28 * \times 484

2.

*

36^{234} \times 33^{512} \times 39^{180} - 54^{29} \times 25^{123} \times 31^{512}

(36^{234}) (33^{512}) (39^{180}) - (54^{29}) (25^{123}) (31^{512})

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