The number of distinct prime factors in (216)3/5 (2500)2/5 (300)1/5 is
None of these
(216)3/5.(2500)2/5(300)1/5=(33.23)3/5(52.102)2/5(3×102)1/5=39/5.29/5(10422)2/5.31/5×102/5=3(95+15).2(95−45).10(85+25)=32.21.102=32.21.22.52=23.32.52∴Number of prime factors=3.