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Question

The number of distinct real roots of ∣ ∣sinxcosxcosxcosxsinxcosxcosxcosxsinx∣ ∣=0 in x[π4,π4] is

A
0
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B
2
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C
1
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D
3
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Solution

The correct option is C 1
∣ ∣sinxcosxcosxcosxsinxcosxcosxcosxsinx∣ ∣=0
Applying R1R1+R2+R3 and taking common from R1, we get
(sinx+2cosx)∣ ∣111cosxsinxcosxcosxcosxsinx∣ ∣=0
Applying C2C2C1 and C3C3C1
(sinx+2cosx)∣ ∣100cosxsinxcosx0cosx0sinxcosx∣ ∣=0
(sinxcosx)2(sinx+2cosx)=0
x=π4, x[π4,π4]

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