The number of distinct real roots of $x^{4} - 4 x + 1 = 0$ is:

2

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4

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1

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0

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Solution

The correct option is A $2$
$f (x) = x^{4} - 4 x + 1 = 0$
$f^{'} (x) = 4 x^{3} - 4 = 4 (x - 1) (x^{2} + 1 + x)$

$\Rightarrow$ Two solutions

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