CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon


Question

The number of distinct real roots of 
x44x3+12x2+x1=0 is 


A
0
loader
B
1
loader
C
2
loader
D
3
loader

Solution

The correct option is C 2
We have x44x3+12x2+x1=0x44x3+6x24x+1+6x2+5x2=0(x1)4+6x2+5x2=0(x1)4=6x25x+2
To solve the above polynomial, it is equivalent to fine intersection points of the curves y=(x1)4 and 
y=6x25x+2ory=(x1)4 and (x+512)2=16
The graph or above two curves as follows. 
Clearly they have two points of intersection.
Hence the given polynomial has two real roots. 
 

Mathematics

Suggest Corrections
thumbs-up
 
1


similar_icon
Similar questions
View More


similar_icon
People also searched for
View More



footer-image