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Question

The number of distinct roots of the quadratic equation ax2+(a2)x+a24=0 when a=2 is

A
1.0
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B
01
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C
1.00
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D
1
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Solution

For the equation ax2+(a2)x+a24=0 when a=2, we can rewrite the equation as
2x2=0x=0
Hence the equation has only 1 distict root.

Also on comparing with the equation px2+qx+r=0, if q=0 and r=0 we know that the roots of the quadratic equation will be {0,0}

Here, a2=0 and a24=0. Hence we can directly say that the roots are {0,0}. Hence the equation has 1 distinct root

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