The correct options are
B n+4C4
C n+4Cn
D (n+1)(n+2)(n+3)(n+4)24
Consider a binomial expansion
(x1+x2+x3+x4...+xm)p
This will have exactly p+m−1Cp distinct terms.
For the above given expression,
m=5 and p=n
Hence the no.of distinct terms will be
n+5−1Cn
=n+4Cn
=n+4Cn+4−n
=n+4C4
=(n+4)(n+3)(n+2)(n+1)4!
=(n+4)(n+3)(n+2)(n+1)24