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Question

The number of distinct terms in the expansion of (x+2y−3z+5w−7u)n is

A
n+1
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B
n+4C4
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C
n+4Cn
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D
(n+1)(n+2)(n+3)(n+4)24
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Solution

The correct options are
B n+4C4
C n+4Cn
D (n+1)(n+2)(n+3)(n+4)24
Consider a binomial expansion
(x1+x2+x3+x4...+xm)p
This will have exactly p+m1Cp distinct terms.
For the above given expression,
m=5 and p=n
Hence the no.of distinct terms will be
n+51Cn
=n+4Cn
=n+4Cn+4n
=n+4C4
=(n+4)(n+3)(n+2)(n+1)4!
=(n+4)(n+3)(n+2)(n+1)24

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