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Question

The number of distinct terms in the expansion of (x+y−z)16 is

A
136
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B
153
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C
16
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D
17
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Solution

The correct option is B 153
We know number of distinct terms in (x1+x2+x3+......+xr)n is n+r1Cr1
Here r=3,n=16
Hence required number of distinct terms is =16+31C31=18C2=153.

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