The number of distinct terms in the expansion of (x+y−z)16 is
A
136
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B
153
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C
16
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D
17
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Solution
The correct option is B153 We know number of distinct terms in (x1+x2+x3+......+xr)n is n+r−1Cr−1 Here r=3,n=16 Hence required number of distinct terms is =16+3−1C3−1=18C2=153.