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Question

The number of distinct terms in the expansion of (x+yz)16 are

A
136
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B
153
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C
16
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D
17
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Solution

The correct option is D 17
We have been given (x+yz)16
(x+yz)16 = 16C0x16yz0+16C1x15yz1+..........16C16x0yz16
Thus, we can see that in each term the powers of the variables x,y and z will be different.
So, there will be 17 terms and all of them will be distinct.

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