The number of distinct zeroes of the polynomial $f (x) = x^{2} - 8 x + 16$ is

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Solution

For finding zeroes of polynomial
$f (x) = 0 \Rightarrow x^{2} - 8 x + 16 = 0 \Rightarrow (x - 4)^{2} = 0 \Rightarrow x = 4, 4$
$∴$ The number of distinct zeroes of the polynomial is $1$

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