The correct option is
C 48
Method For an integer N>1
N=pa×qb×rc×.....
where p,q,r,.... are prime factors of N
and a,b,c,... are prime factors p,q,r... respective;y.
Then, No, of divisor of N=(a+1) (b+1) (c+1)....
In equation, 9600=27×31×52
Here, A=7, b=1, c=2
∴ No. of divisor of 9600 are
=(7+1) (1+1) (2+1)
=8×2×3=48