The number of divisors of apbqcrds where a,b,c,d are primes & p,q,r,sϵ N, excluding 1 and the number itself, is:
A
pqrs
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B
(p+1)(q+1)(r+1)(s+1)−4
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C
pqrs−2
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D
(p+1)(q+1)(r+1)(s+1)−2
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Solution
The correct option is B(p+1)(q+1)(r+1)(s+1)−2 Number of divisors of a number in prime factorised form xaybzc... is given by (a+1)(b+1)(c+1)... This includes the divisor 1 and the number itself. So, number of divisors of the given number excluding 1 and the number itself is (p+1)(q+1)(r+1)(s+1)−2