Question

The number of divitors of $9600$ including $1$ and $9600$ are:

• A. $60$
• B. $58$
• C. $48$
• D. $46$

Answer 1

The correct option is C $48$

$9600=2^7\times 3\times 5^2$

$\therefore$ No. of divisors $=(7+1)\cdot (1+1)\cdot (2+1)=8\times 2\times 3$

$=48$