Question

The number of effusion steps required to convert a mixture of$H_2$ and $O_2$ from 240:1600(by mass) to 3072:20(by mass) is :

Answer 1

The number of diffusion steps $x=\frac{2log\left(\frac{\frac{W_{H2}^{\prime }}{W_{O2}^{\prime }}}{\frac{W_{H2}}{W_{O2}}}\right)}{log\left(\frac{M_{O2}}{M_{H2}}\right)}$
Substitute values in the above expression.
$X=2log\frac{\frac{16\times 3072}{20}}{\frac{16\times 240}{1600}}log\frac{32}{2}=\frac{2log1024}{log14.54}=\frac{6.02}{1.163}=5.2\simeq 5$
Hence, 5 effusion steps will be required.