The number of electric field lines crossing an area A is n1 when A - E- while number of field lines crossing same area is n2 when E makes an angle of 30- with A- then

Name: NEET - 12 - Physics - Introduction to Electric Flux - Session 12 - W13
Uploaded: 2022-07-04T10:36:42+05:30
Description: Given: θ_1=0; θ_2=30^∘ We know that electric flux is given by ϕ = nbsp;E. nbsp;A = E A cosθ = Number of electric field lines crossing given area perpen ...

Given: θ_1=0; θ_2=30^∘ We know that electric flux is given by ϕ = nbsp;E. nbsp;A = E A cosθ = Number of electric field lines crossing given area perpen ...

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Standard XII

Physics

Ampere's Circuital Law

The number of...

Question

The number of electric field lines crossing an area $A$ is $n_{1}$ when $\to A | | \to E$ , while number of field lines crossing same area is $n_{2}$ when $\to E$ makes an angle of $30^{\circ}$ with $\to A$ , then

n_{1} = n_{2}

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n_{1} > n_{2}

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n_{1} < n_{2}

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n_{1} \leq n_{2}

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Solution

The correct option is B $n_{1} > n_{2}$
Given:
$θ_{1} = 0; θ_{2} = 30^{\circ}$

We know that electric flux is given by

$ϕ = \to E . \to A = E A cos θ$ = Number of electric field lines crossing given area perpendicularly

When $\to A | | \to E$ that means $θ_{1} = 0$

So,
$ϕ_{1} = E A cos 0^{\circ} = E A$

$\Rightarrow E A \propto n_{1} . . . . . . . . . . (1)$

When $\to E$ makes an angle of $30^{\circ}$ with $\to A$

So,
$ϕ_{2} = E A cos 30^{\circ} = 0.87 E A$

$\Rightarrow 0.87 E A \propto n_{2} . . . . . . . . . . (2)$

From eqs. $(1)$ and $(2)$ ,

$n_{1} > n_{2}$

Hence, option (b) is the correct answer.

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Ampere's Circuital Law

Standard XII Physics

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The number of electric field lines crossing an area A is n1 when →A||→E, while number of field lines crossing same area is n2 when →E makes an angle of 30∘ with →A, then

The number of electric field lines crossing an area $A$ is $n_{1}$ when $\to A | | \to E$ , while number of field lines crossing same area is $n_{2}$ when $\to E$ makes an angle of $30^{\circ}$ with $\to A$ , then