The number of electron associated with quantum numbers $n = 5, m_{s} = + \frac{1}{2}$ is

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Solution

The correct option is C 25
The number of orbitals possible in a shell with principal quantum number 'n' is ' $n^{2}$ '.
Each orbital can have one electron each of + and - spin.
Number of electrons with $m_{s} = + \frac{1}{2}$ is also 25
Hence, the correct answer is option (c).

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Similar questions

n = 5, m_{s} = + \frac{1}{2}

n = 2, l = 1, m_{l} = 0

n = 4

m_{s} = - \frac{1}{2}

n = 3

m_{s} = - \frac{1}{2}

n = 3, l = 1

m = - 1

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