The number of electrons exchanged in the reaction given below is:
$A l + F e_{3} O_{4} \to A l_{2} O_{3} + F e$

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Solution

$A l + F e_{3} O_{4} \to A l_{2} O_{3} + F e$

$8 A l + 3 F e_{3} O_{4} \to 4 A l_{2} o_{3} + 9 F e$

$∴ 24$ electons are transfered

because $8 + 3 + 4 + 9 + = 24$

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Similar questions

Q. In the reaction,

A l + {F e}_{3} O_{4} \to {A l}_{2} O_{3} + F e

total number of electrons transferred during reaction are:

Q. Balance the given reaction :

F e + H_{2} O \to F e_{3} O_{4} + H_{2}

Q. Consider the reaction:

F e + H_{2} O \to F e_{3} O_{4} + H_{2}

If the number of electrons lost or gained during the changes is

x

. Then, the value of

x

is :

Q. Oxidation number of

F e

F e_{3} O_{4}

is:

${F e}_{2} O_{3}$ + $A l$ $\to$ $F e$ + ${A l}_{2} O_{3}$ + $h e a t$
This is the reaction used in thermite welding process. Calcium can also be used instead of aluminium in this process.

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The number of electrons exchanged in the reaction given below is:Al+Fe3O4→Al2O3+Fe

Al+Fe3O4→Al2O3+Fe8Al+3Fe3O4→4Al2o3+9Fe∴24 electons are transferedbecause 8+3+4+9+=24

The number of electrons exchanged in the reaction given below is:
$A l + F e_{3} O_{4} \to A l_{2} O_{3} + F e$

$A l + F e_{3} O_{4} \to A l_{2} O_{3} + F e$

$8 A l + 3 F e_{3} O_{4} \to 4 A l_{2} o_{3} + 9 F e$

$∴ 24$ electons are transfered

because $8 + 3 + 4 + 9 + = 24$