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Question

The number of electrons having (n×l×m)=0 in Na+ is :

A
2
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B
4
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C
6
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D
7
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Solution

The correct option is B 6
As we know,
principal quantum number denoted by (n)wheren=1,2,3
azimuthal quantum number denoted by ()where=0ton+1
magnetic quantum number denoted by (m)wheremto
spin quantum number denoted by (s)wheres±1/2
Na+=1s22s2p6
As we know,
s have l = 0 and pz have m=0
So, it have six electron with (n×l×m)=0.

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