The number of electrons in 1.6 C charge will be

10^{19}

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10^{20}

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1.1 \times 10^{19}

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1.1 \times 10^{2}

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Solution

The correct option is A $10^{19}$

$n = \frac{q}{e} = \frac{1.6}{1.6 \times 10^{- 19}} = 10^{19}$

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The number of electrons in 1.6 C charge will be

The correct option is A 1019 n=qe=1.61.6×10−19=1019

The correct option is A $10^{19}$

$n = \frac{q}{e} = \frac{1.6}{1.6 \times 10^{- 19}} = 10^{19}$