Question

The number of electrons in $1.6$ gm of $C{H}_4$ is $6.022\times 10x$. What is the value of $x$?

[Round off to nearest integer]

Answer 1

$(12+4)$ gm of $C{H}_4\to Na$ molecules

$\to 10Na$ electrons.

$1.6gm$ of $C{H}_4\to \frac{1.6}{10}\times 10Na$ electrons

$\to Na$ electrons

$\to 6.02\times {10}^{23}$ electrons

$n=23$