Question

The number of electrons in $1.8$ gm of $N{H}_4^{+}$ is $6.022\times 10x$. What is the value of $x$?

[Round off to nearest integer]

Answer 1

$(14+4)$ gm of $N{H}_4^{+}\to$ Na mole celler

$\to 10Na{e}^{⊝}$

$1.8gm$ of $N{H}_4^{+}\to \frac{1.8}{18}\times 10Na{e}^{⊝}$

$\to Na{e}^{⊝}$

$\to 6.022\times {10}^{23}{e}^{⊝}$ of $N{H}_4^{\oplus }$