The number of electrons in Na (11) having $l = 0$ are equal to:

There are two electrons in 1s orbital

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There are two electrons in 2s orbital

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There are two electrons in 2p orbital

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There are one electrons in 3s orbital

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Solution

The correct options are
A There are two electrons in 1s orbital
C There are one electrons in 3s orbital
D There are two electrons in 2s orbital
(A) In $1 s^{2}, n = 1, l = 0$
(B) In $2 s^{2}, n = 2, l = 0$
(B) In $2 p^{6}, n = 2, l = 1$
(D) In $3 s^{1}, n = 3, l = 0$

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