Question

The number of electrons involved in electrode reaction by 1 coulomb charge is:

• A. $6.85\times {10}^{14}$
• B. $19.85\times {10}^{18}$
• C. $6.85\times {10}^{18}$
• D. $16.85\times {10}^{15}$

Answer 1

The correct option is C $6.85\times {10}^{18}$

Faraday's first law states that the mass of any substance deposited or liberated at any electrode is directly proportional to the quantity of electricity passed. i.e., W is proportional to Q,
W $=$ Mass of ions liberated in gm,
Q $=$ Quantity of electricity passed in Coulombs $=$ Current in Amperes ( i ) Time in second (t)
W is proportional to i t
or W $=$ Z i t
Coulomb is the unit of electrical charge.
96500 Coulombs electrons $=$ 1 mole electrons.
1 Coulomb $=$ $6.023\times {10}^{23}/96500=6.85\times {10}^{18}$ electrons.