Question

The number of electrons involved when one faraday of electricity is passed through an electrolytic solution is:

• A. $96500$
• B. $8\times {10}^6$
• C. $12\times {10}^{16}$
• D. $6\times {10}^{23}$

Answer 1

The correct option is D $6\times {10}^{23}$

$1$ Faraday= $96500$ coulombs

$1F$ is charge carried by $1$ mole of electrons so $6\times {10}^{23}$ electrons are involved.