The number of electrons required for deposition of one mole of copper on the cathode during the electrolysis of CuSO $_{4}$ is:

6.0x10

^{23}

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1.2x10

^{24}

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4.8x10

^{24}

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3x10

^{23}

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Solution

The correct option is A 1.2x10 $^{24}$
$2 e^{-} + C u^{2 t} \to C u + 2 e^{-}$

Mole ratio of copper $= \frac{1 m o l C u}{2 m o l e^{-}} .$

Moles of electrons required $\frac{m o l e s o f C u}{m o l e r a t i o} = \frac{1 m o l C u}{\frac{1 m o l C u}{2 m o l e^{-}}} = 2 m o l .$
Number of electrons required $= 2 \times (6.023 \times 10^{23}) = 1.2 \times 10^{24} .$

Hence, the correct option is $B$

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The number of electrons required for deposition of one mole of copper on the cathode during the electrolysis of CuSO4 is:

The correct option is A 1.2x10242e−+Cu2t→Cu+2e−Mole ratio of copper =1molCu2mole−.Moles of electrons required molesofCumoleratio=1molCu1molCu2mole−=2mol.Number of electrons required =2 × (6.023×1023) =1.2 × 1024.Hence, the correct option is B

The number of electrons required for deposition of one mole of copper on the cathode during the electrolysis of CuSO $_{4}$ is: