Question

The number of electrons to be removed from a glass rod in order that it acquires a charge of $1\mu C$ is:

• A. $6.25\times {10}^{12}$
• B. ${10}^{12}$
• C. $6.25\times {10}^{13}$
• D. ${10}^{13}$

Answer 1

The correct option is A $6.25\times {10}^{12}$

Charge to acquire, $Q=1\times {10}^{-6}C$

Electronic charge, $e=1.6\times {10}^{-19}C$

From $Q=ne$, we get:

$n=\frac{Q}{e}=\frac{1\times {10}^{-6}}{1.6\times {10}^{-19}}=6.25\times {10}^{12}$