The number of elements in the power set of the set ${(a, b) : a^{2} + b^{2} = 7, a, b \in Z}$ is

2

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1

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4

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6

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Solution

The correct option is B $1$
Clearly, $a^{2} + b^{2} \neq 7$ for any $a, b \in Z$
$∴$ Given set has no elements.
Hence, the number of elements in power set $= 2^{0} = 1$

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