Question

The number of elements in the power set of the set $\left\{\right(a,b):a^2+b^2=7,a,b\in Z\}$ is

• A. 1.0
• B. 1.00
• C. 1

Answer 1

Answer: (A), (B), (C)

Clearly, $a^2+b^2\ne 7$ for any $a,b\in Z$
$\therefore$ Given set has no elements.
Hence, the number of elements in power set $=2^0=1$