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Standard XII

Chemistry

Percentage Composition

The number of...

Question

The number of equivalents for the following molecules are given as
(a) $1.6$ g $O_{2}$ gas $= 0.2$
(b) $0.49$ g $H_{2} S O_{4}$ $= 0.01$
(c) $1.80$ g $H_{2} O$ $= 0.2$
(d) $1.6$ g $C H_{4}$ $= 0.4$
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Solution

(a) $1.6$ g $O_{2} = \frac{1.6}{8} = 0.2$ equivalent.
(b) $\frac{0.49}{49} = 0.01$ (equivalent weight of $H_{2} S O_{4} = 49$ )

(c) $\frac{1.80}{9} = 0.2$ (equivalent weight of $H_{2} O = 9$ )
(d) $\frac{1.6}{4} = 0.4$ (equivalent weight of $C H_{4} = 4$ )

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The number of equivalents for the following molecules are given as(a) 1.6 g O2 gas =0.2(b) 0.49 g H2SO4 =0.01(c) 1.80 g H2O =0.2(d) 1.6 g CH4 =0.4If true enter 1, else enter 0.

(a) 1.6 g O2=1.68=0.2 equivalent.(b) 0.4949=0.01 (equivalent weight of H2SO4=49) (c) 1.809=0.2 (equivalent weight of H2O=9)(d) 1.64=0.4 (equivalent weight of CH4=4)

The number of equivalents for the following molecules are given as
(a) $1.6$ g $O_{2}$ gas $= 0.2$
(b) $0.49$ g $H_{2} S O_{4}$ $= 0.01$
(c) $1.80$ g $H_{2} O$ $= 0.2$
(d) $1.6$ g $C H_{4}$ $= 0.4$
If true enter 1, else enter 0.

(a) $1.6$ g $O_{2} = \frac{1.6}{8} = 0.2$ equivalent.
(b) $\frac{0.49}{49} = 0.01$ (equivalent weight of $H_{2} S O_{4} = 49$ )

(c) $\frac{1.80}{9} = 0.2$ (equivalent weight of $H_{2} O = 9$ )
(d) $\frac{1.6}{4} = 0.4$ (equivalent weight of $C H_{4} = 4$ )