The number of ether isomers possible for the molecular formula $C_{5} H_{12} O$ are:

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Solution

The correct option is B 6
The number of ether isomers possible for the molecular formula $C_{5} H_{12} O$ is six. These are as shown
$C H_{3} - C H_{2} - C H_{2} - C H_{2} - O - C H_{3}$
$C H_{3} - C H_{2} - C H_{2} - O - C H_{2} - C H_{3}$
$C H_{3} - C H_{2} - C H (C H_{3}) - O - C H_{3}$
$C H_{3} - C H (C H_{3}) - C H_{2} - O - C H_{3}$
$C H_{3} - C H (C H_{3}) - O - C H_{2} - C H_{3}$
$C H_{3} - C H (C H_{3})_{2} - O - C H_{3}$

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